## Saturday, May 30, 2015

### Can you explain this mathematical absolute?

Here is a fun little result, which is a mathematical absolute, with all positive integers:

x + y + j + 1 = n2 or 2n2

if x = 1 mod D, x2 - Dy2 = 1, and j = (x+Dy-1)/D

For example, 82 - 7*32 = 1, so x = 8, and 8 mod 7 = 1.

j = (8 + 7*3 - 1)/7 = (7 + 7*3)/7 = 4

8 + 3 + 4 + 1 = 16 = 42

That's a simple example to make this post easy to write for me, but the result is true over infinity.

So whenever x = 1 mod D, with x2 - Dy2 = 1, then these rules are forced, absolutely.

Seem easy or trivial?

It's another key piece of the explanation for an ancient math mystery.

James Harris

## Sunday, May 10, 2015

### Part of the key to an ancient math mystery

Known since antiquity: x2 - Dy2 = 1

The smallest integer solution by absolute value for x and y, not zero is called the fundamental solution. Sometimes it can be quite large, but why?

For example, for D = 61, the fundamental solution is quite large:

17663190492 - 61(226153980)2 = 1

Part of the key to the answer--hidden in simple math for millennia:

(D-1)j2 + (j - 1)2 = (x+y)2,

where j = (x+Dy+1)/D, so our x, gives: j = 255110030.

60*2551100302 + 2551100292 = 19924730292

A connection like no other, an ellipse to a hyperbola--an answer? Part of it.

Here's another example, for D = 313, which I found in a Wikipedia article:

321881208291348492 - 313(1819380158564160)2 = 1

so:

j = 1922217605302610

312*19222176053026102 + 19222176053026092 = 340075009876990092

That one is too big for my pc calculator, though I could program something to check it, I'll use another trick.

I know that when x = -1 mod D that x+y+j-1 must be a perfect square or twice one.

That's an absolute by the way.

And yup, x+y+j-1 = 2*1340330532 so it works! Oh yeah, same thing works above, which is another clue.

If x = -1 mod D and x2 - Dy2 = 1, with all nonzero positive integers, then these equations apply, across infinity. So oh yeah, it's an infinity result. I get a kick out of those things, try now to note when I have one.

Oh yeah, remembered I could use Wolfram Alpha and everything checked out ok there.

Who knew? Ellipses and hyperbolas, like a freaky number family?

Of course I have the full answer. It's ok. To me it's just nice to know, but I like having answers to mysteries.

James Harris