Found myself intrigued by putting up just enough information to do the calculations for square root of 3 with one of an infinity of possible relations:
sqrt(3) approximately equals xn+1/yn+1, where:
xn+1 = 97xn + 168yn
yn+1 = 56xn + 97yn
and x0 = 1, and y0 = 0;
Does an n exist for: x = 1351, and y = 780?
(If you figure it out, and answer is yes, please give n in comments.)
With those if it does then: xn+1 = 262087, and yn+1 = 151316
And 262087/151316 equals approximately: 1.73205080758
Correct for sqrt(3), same number of digits: 1.73205080756
And differs from sqrt(3) by approximately: 1.26e-11
That pc calculator is so handy.
Oh yeah, negative DOES work. Just been kind of sloppy, and just talking the positive, so you can start with: x0 = -1, and y0 = 0
The math does NOT care. And of course you have two solutions! Positive and negative for sqrt(3). So yes, try x and y with different negations and see what happens! (Still works.)
Wondering if should fix prior posts, occuring to me don't really care as is freaking obvious anyway. Moving on to other more important things.
Still just doing these for fun.